Question

Find the area of a rectangle whose length is 6 inches less than 5 times the width and whose perimeter is 8 inches more than twice the length

Answer 1

You have l = 5w - 6; P = 8 + 2l; where l = the length of the rectangle ; w = the width of the rectangle; P = the perimeter of the rectangle;

P = 2l + 2w;

Then, 2l + 2w = 8 + 2l ;
2w = 8 ;
w = 4 ;
l = 5*4 - 6 ;
l = 14.