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Equation of a line that is perpendicular y=-5/6x-2 with the slope being (10,15)?

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EQUATION OF A LINE IS y = mx + c

When lines are perpendicular, the values in front of the x multiply to -1

-5/6 * ? = -1
-1/-(5/6) = 6/5

so far we have: y = 6/5x + c

From the coordinates x = 10, y = 15
Substitute these into equation

15 = (6/5 * 10) + c
15 = 12 + c
3 = c


ANSWER IS y = 6/5x + 3
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