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If the velocity of an object changes from 65 m/s to 98 m/s during a time interval of 12 s, what is the acceleration of the object?

A. 2.75 m/s
B. 13.58 m/s
C. 33 m/s
D. 5.42 m/s

2 Answers

5 votes
The question is asking to calculate the acceleration of the object if the velocity of an abject changes from 65 m/s to 98 m/s during a time interval of 12s, and base on my calculation, the possible answer would be letter A. 2.75 m/s. I hope you are satisfied with my answer and feel free to ask for more 
User Roenving
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Answer

Find out the what is the acceleration of the object .

To prove

Formula


Acceleration = (Final\ velocity - Intial\ velocity)/(Time )

Where

t = the time in which the change occurs

As given

If the velocity of an object changes from 65 m/s to 98 m/s during a time interval of 12 s .

Final velocity = 98 m/s

Intial velocity = 65 m/s

Time = 12 s

Put in the formula


Acceleration = (98 - 65)/(12)


Acceleration = (33)/(12)

Acceleration = 2 .75 m/s ²

Option (A) is correct .




User Houssem TRABELSI
by
6.7k points