Question

-6=61–2 – h) + 3 + j; use h = 3, and j = 6

Answer 1

For this case we have the following expression given:

`(-6)/(6(-2-h))+3+j\text{ , h= }3\text{, j=6}`

We can begin doing this:

`(-6)/(-6(2+h))+3+j`

We can cancel -6 and we got:

`(1)/(2+h)+3+j`

Now we can replace h=3 and j= 6 and we got:

`(1)/(2+3)+3+6=\text{ }(1)/(5)+9=\text{ }(46)/(5)`