Question

How do i solve 3x² - 8x + 2 = 0 using quadratic formula?

Answer 1

`x = (-b +/- √(b^2 - 4ac))/(2a)`

`x = (-(-8) +/- √((-8)^2 - 4(3)(2)))/(2(3))`

`x = (8 +/- √(64 - 24))/(6)`

`x = (8 +/- √(40))/(6)`

`x = (8 +/- 6.31)/(6)`

`x = (14.32)/(6)` x ≈ 2.39

`x = (1.68)/(6)` x ≈ 0.28

Answer 2

`3x^2 - 8x + 2 = 0\\ \\a=3 , \ \ b=-8 , \ \ c=2 \\ \\x_(1)=(-b-√(b^2-4ac))/(2a) =(8-√( (-8)^2-4 \cdot 3\cdot 2))/(2 \cdot 3) =(8-√( 64-24 ))/(6) =\\ \\ =(8-√(40 ))/(6) = ( 8-√(4\cdot 10 ) )/(6) = ( 8-2√( 10 ))/(6) = (2 (4-√( 10 )))/(6) = ( 4-√( 10 ) )/(3)`


`x_(2)=(-b+√(b^2-4ac))/(2a) =(8+√( (-8)^2-4 \cdot 3\cdot 2))/(2 \cdot 3) = ( 4+√( 10 ) )/(3)`