Question

The sides of a square are three to the power of two sevenths inches long. What is the area of the square?

nine to the power of four sevenths square inches
three to the power of four sevenths square inches
three to the power of the fraction four over forty nine square inches
nine to the power of the fraction four over forty nine square inches
I say its B ( 2nd one )

Answer 1

The area is (3^{2/7} )^2[/tex], or 

Answer 2

we know that

Area of the square=
`x^(2)`

where

x is the length side of the square

in this problem

`x=3^{(2)/(7)}` in

so

`Area=(3^{(2)/(7)})^(2) \\ Area=3^{((2*2))/(7)} \\ Area=3^{(4)/(7)}`in²

therefore

the answer is the option

three to the power of four sevenths square inches