Write the quadratic equation whose roots are 2 and -6, and whose leading coefficient is 1 . (Use the letter to represent the variable.) =0

asked Sep 18, 2015 9.8k views

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$(x-2)(x+6)=\\ x^2+6x-2x-12=\\ x^2+4x-12$

Moosa Baloch answered Sep 20, 2015

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$roots\ are\ 2\ and\ -6\ and\ a=1\ then:\\\\1(x-2)(x+6)=0\\\\x\cdot x+x\cdot6-2\cdot x-2\cdot6=0\\\\x^2+6x-2x-12=0\\\\x^2+4x-12=0$

Noelle answered Sep 22, 2015

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