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Factor the trinomial, 14c³-33c²+18c= ______ (factor completely)
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Factor the trinomial, 14c³-33c²+18c= ______ (factor completely)

User Ravi Makvana
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c(14c2 - 33c + 18)
c(2c - 3)(7c - 6) << is your final answer
User Ksarmalkar
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1 vote

14c^3-33c^2+18c=\\ c(14c^2-33c+18)=\\ c(14c^2-21c-12c+18)=\\ c(7c(2c-3)-6(2c-3))=\\ c(7c-6)(2c-3)
User Localghost
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