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Find dy/dx 2x+3y=sinx
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Find dy/dx
2x+3y=sinx

User Francois Taljaard
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1 Answer

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2x+3y=sinx\\\\3y=sinx-2x\ \ \ \ /:3\\\\y=(1)/(3)(sinx-2x)\\\\(\delta y)/(\delta x)=\left[(1)/(3)(sinx-2x)\right]'=(1)/(3)\left[(sinx)'-(2x)'\right]=(1)/(3)(cosx-2)
User Alberto Acepsut
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