Question

a bullet is fired horizontally with a speed of 524 m/s from a height of 22m above the ground. calculate where it will hit the ground

Answer 1

Given data:

* The height of the bullet is 22 m.

* The speed of bullet in the horizontal direction is 524 m/s.

Solution:

By the kinematics equation, the time taken by the bullet to reach the ground is,

`h=u_yt+(1)/(2)gt^2`

where u_y is the vertical velocity component, t is the time taken to reach the ground, g is the acceleration due to gravity, and h is the height of the bullet,

Substituting the known values,

`\begin{gathered} 22=0+(1)/(2)*9.8* t^2 \\ t^2=(22*2)/(9.8) \\ t^2=4.49 \\ t=2.12\text{ s} \end{gathered}`

Thus, the time taken by the bullet to reach the ground is 2.12 seconds.

By the kinematics equation for the horizontal motion, the horizontal range of the bullet is,

`R=u_xt+(1)/(2)at^2`

where u_x is the horizontal component of the velocity, a is the acceleration along the horizontal direction, t is the time taken to reach the ground and R is the horizontal range,

Substituting the known values,

`\begin{gathered} R=524*2.12+0 \\ R=1110.9\text{ m} \end{gathered}`

Thus, the horizontal range of the bullet is 1110.9 meters.

Hence, the bullet hit the ground at 1110.9 meters.