Question

Calculate the conductance of a conduit the cross-sectional area of which is 3.0 cm2 and the length of which is 9.0 cm, given that its conductivity is 0.80 ohm-1cm-1.

Answer 1

for resistance we have R=ρ l/a
thus for conductance we have K=σ a/l
conductance,K=1/R
conductivity,σ =1/ρ

σ = .80 Ω-1 cm-1
l =9 cm
a = 3 cm²
K=.80 ×3/9
=0.26 Ω-1

Answer 2

Answer:
`0.266 ohm^(-1)`

Explanation: Specific conductance or conductivity is the conductance for unit volume of a solution.

`\kappa=C* (l)/(a)`

where,

`\kappa` =Specific conductance or Conductivity=
`0.80ohm^(-1)cm^(-1)`

C = Conductance = ?

l = length= 9.0 cm

a = area = 3.0
`cm^2`

`(length)/(area)`= cell constant =
`(9.0cm)/(3.0cm^2)=3cm^(-1)`

`0.80ohm^(-1)cm^(-1)=C* 3cm^(-1)`

`C=0.266 ohm^(-1)`