Question

A drawer has some red ,green and blue marbles.there are 33 marbles . there are 4 times as many red marbles as green marbles.there are half as many blue marbles as green marbles.

how many blue marbles are in the drawer?

Answer 1

`g-green\ marbles\\r-red\ marbles\\b-blue\ marbles\\g+r+b=33\\\\4g-red\ marbles\\(1)/(2)g-blue\ marbles\\\\g+4g+(1)/(2)g=33\\\\5(1)/(2)g=33\\\\(11)/(2)g=33\ \ \ \ /\cdot(2)/(11)\\\\g=3\\\\Answer:b=(1)/(2)g\to b=(1)/(2)\cdot6=3`

Answer 2

The number of blue marbles be 3.

Explanation:

As given

A drawer has some red ,green and blue marbles.

There are 33 marbles .

there are 4 times as many red marbles as green marbles.

Let us assume that the number of green marbles be g .

Than Red marbles = 4g

There are half as many blue marbles as green marbles.

Than

`Number\ of\ blue\ marbles =\frac {Number\ of\ green\ marbles}{2}`

`Number\ of\ blue\ marbles =(g)/(2)`

Than the equation becomes

`g + 4g + (g)/(2) = 33`

Than simplify the above

`2g + 8g + g = 33* 2`

`11g = 66`

`g= (66)/(11)`

g = 6

`Number\ of\ blue\ marbles =(6)/(2)`

Number of blue marbles = 3

Therefore the number of blue marbles be 3 .