Question

Can anyone help me?

Answer 1

Given:

A right angle triangle ABC, right angled at C.

To find:

The measure of θ.

Solution:

In a right angle triangle,

`\tan \theta=(Opposite)/(Adjacent)`

In triangle ABC,

`\tan \theta=(AC)/(BC)`

`\tan \theta=(2.7)/(5)`

`\tan \theta=0.54`

It can be written as

`\theta=\tan^(-1)0.54`

`\theta\approx 28.369`

Therefore, the measure of θ is 28.369.