Question

A gas has a pressure of 6.5 atm at a temperature of 500. K. At what temperature will the pressure be 4.8 atm?

Answer 1

To solve this question we have use Gay-Lussac's Law:

`(P1)/(T1)=(P2)/(T2)`

Where P1 and P2 are the pressures and T1 and T2 are the temperatures.

In this case, we know the values of P1, P2 and T1 and we have to find T2:

`\begin{gathered} T2=T1\cdot(P2)/(P1) \\ T2=500K\cdot(4.8atm)/(6.5atm) \\ T2=369.23K \end{gathered}`

The pressure will be 4.8atm at 369.23K.