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Can anyone help me?pls

Can anyone help me?pls-example-1
User CMB
by
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1 Answer

5 votes

Answer:

b = 8.89, c = 11.96 and m∠B = 48°

Explanation:

From the given triangle ABC,

We will apply sine ratio for angle A,

sin(A) =
\frac{\text{Opposite side}}{\text{Hypotenuse}}

sin(42)° =
(BC)/(AB)

sin(42)° =
(8)/(AB)

AB =
\frac{8}{\text{sin}(42)}

AB = 11.96

c = 11.96

By triangle sum theorem,

m∠A + m∠B + m∠C = 180°

42° + m∠B + 90° = 180°

m∠B = 180 - 132

m∠B = 48°

By cosine ratio of angle A,

cos(A) =
\frac{\text{Adjacent side}}{\text{Hypotenuse}}

cos(42)° =
(AC)/(AB)

AC = AB.cos(42)°

AC = (11.96)cos(42)°

AC = 8.89

b = 8.89

User Mouloud
by
3.5k points