When x = 3 and y = 5, by how much does the value of 3x^2 – 2y exceed the value of 2x^2 – 3y ? F. 4 G. 14 H. 16 J. 20 K. 50

asked Jul 7, 2015 89.9k views

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When x = 3 and y = 5, by how much does the value of 3x^2 – 2y exceed the value of 2x^2 – 3y ?

F. 4
G. 14
H. 16
J. 20
K. 50

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3 votes

$3\cdot3^2-2\cdot5-(2\cdot3^2-3\cdot5)=27-10-(18-15)=17-3=14$

Jayram answered Jul 11, 2015

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