58.1k views
1 vote
What's the vertex form of y=6x^2-12x+1

What's the vertex form of y=6x^2-12x+1-example-1
User Deovandski
by
7.6k points

1 Answer

5 votes

The\ vertex\ form\ of\ y=ax^2+bx+c:y=a(x-h)^2+k\\\\where:h=(-b)/(2a)\ and\ k=(-(b^2-4ac))/(4a)\\-------------------------------\\y=6x^2-12x+1\to a=6;\ b=-12;\ c=1


h=(-(-12))/(2\cdot6)=(12)/(12)=1\\\\k=(-[(-12)^2-4(6)(1))/(4(6))=(-(144-24))/(24)=(-120)/(24)=-5\\\\vertex:(1-5)


the\ vertex\ form:\\\boxed{y=6(x-1)^2-5}
User GameKyuubi
by
7.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories