Question

A bag of apples weighs 7 7/8 pounds and a full bag costs $10.88. By weight 1/18 of the apples are rotten . What is the cost of the bag if the bad apples are removed?

Answer 1

Try Analysing The Information Like This, Step by Step;

1. We know that a full bag of 7 7/8 pounds and is $10.88.
2. Now we subtract the bad apples 7 7/8-1/18= a (now we have no bad apples).
3. Part 'a' answer will give you a no. in pounds.
4. Part 'b' - we have to find out $10.88/7 7/8 - 1/18 / 2 to give you the answer.

I hope this helps, sorry I couldn't really help you :)

Answer 2

Answer: Hello there!

We know that a bag of apples weighs (7 + 7/8) lb and costs $10.88

But 1/18 of the apples are rotten, if we remove the rotten apples, we still have the other 17/18 portion of the bag to pay.

then; if the full bag costs $10.88, how much does it cost a 17/18 of the bag?

this is (17/18)*$10.88 = $10.28

Then if you remove 1/18 of the apples, the bag costs 10.28 dollars.

notice that I did not use the weight of the apples, in a lot of math problems you will have more information than the needed, and you need to know when the information is useful and when it is not.