Question

ANSWER ALL (a-d) FOR 30 POINTS - EASY

a. Write an expression for the perimeter a playground using the formula for perimeter.

b. The width of a playground is 20 yards more than six times the length. Write an expression for the perimeter using this information.

c. Write an equation using the expression from parts a and b. Solve the equation for L.

d. If the playground's width is 32 yards, what is the length?

NO IMAGE AVAILABLE. PLAYGROUND SHAPE: Rectangle/square.

Answer 1

Part a.

The perimeter formula is: P = 2w + 2L

Your answer for part A is P = 2w + 2L


Part b.

They tell us in part b, that:
w = 6L + 20

Substitute that into what we got for part a.

P = 2(6L + 20) + 2L
P = 12L + 40 + 2L
P = 14L + 40

Your answer for partb is P = 14L + 40


Part c.

So we take what we got from part b, and solve for L.

P = 14L + 40
14L = P - 40


`L = \boxed{(P-40)/(14)}`

That is your answer for part 3 ^


part d.

Plug in w = 32 into what we first got in part b.

w = 6L + 20
32 = 6L + 20
6L = 12

L = 2

Your answer for part d is L = 2

:D