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The crew on a fishing boat caught four fish that weighed a total 1,092 pounds. The tarpon weighed twice as much as the amberjack and the white Marlin weighed twice as much as the tarpon. The weight of the tuna was 5 times the weight of the amberjack. How much did each fish weigh?

User Jagan N
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1 Answer

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Let X be the Amberjack; Tarpon = 2 Amberjacks = 2X
White Marlin = 2 Tarpons = 2 * 2X = 4X
Tuna = 5 Amberjacks = 5X

Amberjack + Tarpon + White Marlin + Tuna = 1,092 pounds

X + 2X + 4X + 5X = 1,092 POUNDS

12X = 1,092 POUNDS
X = 1,092/12
X = 91 POUNDS = weight of the Amberjack

Amberjack = X = 91 lbs
Tarpon =2 Amberjacks = 2*91 = 182 lbs
White Marlin = 2 Tarpons = 2 * 182 = 364 lbs
Tuna = 5 Amberjacks = 5 * 91 = 455 lbs

91 lbs + 182 lbs + 364 lbs + 455 lbs = 1,092 lbs

User Vadym
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