Question

A stone is dropped from the height of 121m and reaches to the earth in 10 sec with an acceleration of 20m/s square find the initial velocity of the stone​

Answer 1

question:-

• A stone is dropped from the height of 121m and reaches to the earth in 10 sec with an acceleration of 20m/s square find the initial velocity of the stone

Given :-

• Height = 121 m

• Time = 10 sec

• Acceleration = 20 m/s²

To Find :-

• Initial Velocity

Solution :-

As we know that,

`\boxed{ \sf \: {v}^(2) - {u}^(2) = 2as }`

• V = Final Velocity
• U = Initial Velocity
• A = Acceleration
• S = Distance

According to the question,

0² - u² = 2(20)(121)

0 - u² = 4840

-u² = 4840

-u = √4840

u = -69.5 m/s

Answer:-

The initial velocity of the stone is -69.5 m/S.