Question

Calculate the ratio of change in the mass of the molecules of a gas to the initial mass, if its

speed is reduced to half and the ratio of initial and final pressure is 3:4.

Hint : P =1/3 M/V.v²
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Answer 1

Answer:

Required Answer is as follows :-

• 
  `\sf (P _(i))/( P_(f)) = (3)/(4)`

• 3/4 = (⅓ × m₁/Volume × V²)/(⅓ × m₂/Volume) × (V/2)²

• ¾ = m₁/Volume × (V)²/m₂/Volume × (V/2)²

• ¾ = m₁ × (V)²/m₂ × (V²/4)

• ¾ = m₁/m₂ × 4

• m₂ = 4 × 4/3 = 16/3m₁

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Now,

• ∆m = m₂ - m₁
• ∆m = 16m₂/3 - m₁ = 13m₁/3
• Ratio = (13m₁/3)/ m₁
• Ratio = 13/3

Ratio = 13:3

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Know More :-

Mass => It is used to measure it's resistance to its acceleration. SI unit of mass is Kg.
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