Answer: The correct answer is Option B.
Step-by-step explanation: The compound given to us is
. To write the IUPAC name for this compound, we need to follow some rules:
1. First write the name of the cation with its oxidation state in roman numbers.
2. Then write the name of the anion which may be a polyatomic ion or a non-metal.
3. The anion is used with a suffix '-ide'. Example: For chlorine, the anion would be named as chloride, for sulfur, the anion would be sulfide.
For the given compound, 2 silver atoms are needed to neutralize the charge on 1 sulfur atom.
Hence, the oxidation number of silver atom is '1'. So, the IUPAC name for the compound will be silver (I) sulfide.
Therefore, the correct option is B.