Ok, so:
Let's say you have 5 cheeses A,B,C,D and E.
You want to make a combination of 2 cheeses.
These are the possible combinations.
AB, AC, AD, AE, BC, BD, BE, CD, CE, DE.
So, there are 10 possibilities to make a combination of 2 cheeses.
Now, we also have 10C3 choices of toppings. Because, we have a combination of 10 different toppings and 3 topping to choose.
Now, remember that:
In this case, we have n = 10 and r = 3.
If we replace in the equation, we obtain 10C3 = 120.
So, there are 120 possibilities to make a combination of 3 toppings.
Finally, we multiply the possibilities we found before.
120 * 10 = 1200
Therefore, a pizza can be made with 2 cheese and 3 toppings in 1200 ways.