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6. How much heat is lost cooling 25 grams of water from 90°C to 45°C?

6. How much heat is lost cooling 25 grams of water from 90°C to 45°C?-example-1
User Zlemini
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1 Answer

4 votes

Answer:

4,7025 (kJ).

Explanation:

1) according to the condition: m=25 gr.; t₂=90; t₁=45; c=4.18 J/(g°C);

2) the formula of required heat is

Q=c*m*(t₂- t₁);

3) according to the formula of heat:

Q=4.18*25*45=4702.5 (J).

User Uchuugaka
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