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Use Properties of Equality to solve

-3(4-a)=6

5(x+6)=45

User Meir Maor
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1 Answer

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Use distributive property:
a(b\pm c)=ab\pm ac


-3(4-a)=6\\\\(-3)(4)+(-3)(-a)=6\\\\-12+3a=6\ \ \ |add\ 12\ to\ both\ sides\\\\3a=18\ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{a=6}



5(x+6)=45\\\\(5)(x)+(5)(6)=45\\\\5x+30=45\ \ \ \ |subtract\ 30\ from\ both\ sides\\\\5x=15\ \ \ \ |divide\ both\ sides\ by\ 5\\\\\boxed{x=3}
User Jaguar
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