225k views
5 votes
Solve this simultaneous equation?

4x + y = 25
x - 3y = 16

2 Answers

4 votes

Final answer:

To solve the simultaneous equations, the elimination method was used. After multiplying the second equation by 4 and subtracting the first equation, y = -3 was determined. Substituting y into the first equation gave x = 7.

Step-by-step explanation:

To solve the simultaneous equations 4x + y = 25 and x - 3y = 16, we can use either the substitution method or the elimination method. Here, we'll use the elimination method:

Multiply the second equation by 4 to make the coefficients of x the same: 4(x - 3y) = 4×16, which simplifies to 4x - 12y = 64.

Subtract the first equation from this new equation to eliminate x: (4x - 12y) - (4x + y) = 64 - 25, which simplifies to -13y = 39.

Divide by -13 to solve for y: y = -3.

Substitute y back into the first equation to find x: 4x + (-3) = 25, so 4x = 28 and thus x = 7.

Therefore, the solution to the simultaneous equations is x = 7 and y = -3.

User Hiran
by
8.2k points
1 vote
x-3y=16 -> x=16+3y Put this x into the first equation -> 4(16+3y) +y=25 -> 64+12y+y=25 -> 13y=25-64 -> y= -3 Put this y into first or second equation ( it's up to you :) X-3y=16 -> x-3(-3)=16 -> x+9=16 -> x = 7 --->> (7;-3) Good Luck
User Rufus
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories