Solving by factoring 10p²+6=476

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asked Jan 17, 2015 191k views

2 votes

Solving by factoring 10p²+6=476

Mathematics
high-school

Jd Prajapati asked

by Jd Prajapati

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2 Answers

6 votes

$10p^2+6=476\\ 10p^2-470=0\\ 10(p^2-47)=0\\ p=-√(47) \vee p=√(47)$

Jvdneste answered Jan 19, 2015

by Jvdneste

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3 votes

$10p^2+6=476\\ \\ 10p^2+6-476 =0 \\ \\10p^2-470 =0\ \ /:10 \\ \\ p^2-47 =0 \\ \\(p-√(47))(p+√(47))=0 \\ \\p-√(47)=0 \ \ or \ \ p+√(47) =0 \\ \\p=√(47) \ \ or \ \ p=-√(47)$

Eduard Thamm answered Jan 21, 2015

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