Question

Please solve and show work if you can!

Answer 1

`( x+2 )/(2) \cdot ( 4x+20 )/(x^2+6x+8 ) \\\\x^2+6x+8\\eq 0\\ \\x^2+4x +2x+8 \\eq 0 \\ \\ x(x+4)+2(x+4)\\eq 0\\ \\(x+4)(x+2)\\eq 0`


`x+4 \\eq 0 \ \ \wedge \ \ x+2\\eq 0\\ \\ x\\eq -4 \ \ \wedge \ \ x\\eq -2 \\ \\ D=R\setminus \left \{ -4,-2 \right \}`


`( x+2 )/(2) \cdot ( 4x+20 )/(x^2+6x+8 ) =(\\ot( x+2 )^1)/(\\ot2^1) \cdot ( \\ot4^2(x+5) )/(\\ot(x+2)^1(x+4) ) =(2(x+5))/(x+4)`

Answer 2

`(x+2)/(2)\cdot(4x+20)/(x^2+6x+8)=\\ (x+2)/(2)\cdot(2(2x+10))/(x^2+2x+4x+8)=\\ (x+2)\cdot(2x+10)/(x(x+2)+4(x+2))=\\ (x+2)\cdot(2x+10)/((x+4)(x+2))=\\ (2x+10)/(x+4)`