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Even if I have use bidmas I'm still confuse with this equation (-7i)(2+i)+(2i)(-7i)
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Even if I have use bidmas I'm still confuse with this equation
(-7i)(2+i)+(2i)(-7i)

User Mission
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Assuming "i" is an imaginary unit:

(-7i)(2+i)+(2i)(-7i)=\\ -14i+7+14=\\ 21-14i
User Scls
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