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Quadrilateral ABCD has the following vertices:

A(0,6)
B(3,5)
C(0, -4)
D(-3,-3)
Also, angle a is a right angle.
Is quadrilateral ABCD a rectangle, and why?

User Svyatoslav
by
3.6k points

2 Answers

4 votes

Answer:

Yes, because opposite sides are parallel, and \angle A∠Aangle, A is a right angle.

Explanation:

khan academy

User Karambaq
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2.9k points
12 votes

9514 1404 393

Answer:

yes

Explanation:

The figure can be shown to be a parallelogram by showing the sum of endpoints of the diagonals is the same.

A +C = B +D

(0, 6) +(0, -4) = (0, 2) = (3, 5) +(-3, -3) . . . . diagonals bisect each other

If the diagonals of a quadrilateral bisect each other, it is a parallelogram. A parallelogram with a right angle is a rectangle. So, ABCD is a rectangle.

_____

Additional comment

The midpoint of each diagonal is half the sum of the end point coordinates. That is, the midpoints are (0, 2)/2 = (0, 1). Since calculation of the midpoints requires both sums be divided by 2, we can tell the midpoints are the same if the sums are the same.

Quadrilateral ABCD has the following vertices: A(0,6) B(3,5) C(0, -4) D(-3,-3) Also-example-1
User Diego Dupin
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2.9k points