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5 votes
At a hockey game, a vender sold a combined total of

114
sodas and hot dogs. The number of hot dogs sold was
52
less than the number of sodas sold. Find the number of sodas sold and the number of hot dogs sold.

2 Answers

5 votes

Final answer:

The problem involves determining the number of sodas and hot dogs sold at a hockey game, with the number of hot dogs being 52 less than the number of sodas, out of a total of 114. Solving through simple algebra, we find that 83 sodas and 31 hot dogs were sold.

Step-by-step explanation:

The question poses a problem involving a total of 114 sodas and hot dogs sold at a hockey game, with the number of hot dogs being 52 less than the number of sodas. To find the specific numbers sold of each item, let's define the number of sodas sold as s. Then, the number of hot dogs sold is s - 52. We are given that the combined total is 114, so we can set up the equation:

s + (s - 52) = 114.

Combining like terms, we get:

2s - 52 = 114.

Add 52 to both sides to isolate the terms with s:

2s = 166.

Divide by 2 to solve for s:

s = 83.

Therefore, 83 sodas were sold. To find the number of hot dogs, subtract 52 from 83:

83 - 52 = 31.

So, 31 hot dogs were sold. We have now found the number of sodas and hot dogs sold at the hockey game.

User Nitika Bansal
by
8.2k points
6 votes

you said that the vender sol 114 sodas and the hot dogs were less than the sodas by 52 now subtract 114-52=62 so the sodas are 114 and the hot dogs are 52
User Nimelrian
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8.0k points