Question

need help.    solve for y.  try factoring first if not possible or difficult use quadratic formula.               y²-6y+6=0

Answer 1

`y^2-6y+6=0\\ y^2-6y+9-3=0\\ (y-3)^2=3\\ |y-3|=\sqrt3\\ y-3=\sqrt3 \vee y-3=-\sqrt3\\ y=3+\sqrt3 \vee y=3-\sqrt3`

Answer 2

`y^2-6y+6=0\\ \\a=1 , \ b=-6, \ c=6 \\ \\\Delta =b^2-4ac = (-6)^2 -4\cdot1\cdot6 = 36-24=12\\ \\√(\Delta )= √(12)=√(4\cdot 3)=2√(3) \\ \\x_(1)=(-b-√(\Delta) )/(2a)=(6-2√(3))/(2 )=(2( 3- √(3)))/(2)= 3- √(3)`


`x_(2)=(-b+√(\Delta) )/(2a)=(6+2√(3))/(2 )=(2( 3+ √(3)))/(2)= 3+ √(3)`