Question

Im having trouble understanding what the (-) after the x applies to. does it make everything in the () negative therefore i will distribute by (6*-x) and (6*-2)?

6-(x+2)≥4-9x

Answer 1

`x \ge 0`

Explanation:

Given

`6-(x+2) \ge 4-9x`

Required

Solve

`6-(x+2) \ge 4-9x`

When you distribute -(x+2), the expression becomes:

`6-x-2 \ge 4-9x`

Collect Like Terms

`9x-x \ge 4-6+2`

`8x \ge 0`

Divide both sides by 8

`x \ge (0)/(8)`

`x \ge 0`