Question

Solve for n. 3(n-19)/5=0

Answer 1

3( n - 19 ) = 0 ;
n - 19 = 0 ;
n = 19 .

Answer 2

When you have a fraction like this, just know that the denominator does not matter. The numerator does because 0/any number = 0.
There are many ways to solve this:
Distribute

`(3n-57)/(5) =0`

`(3n-57)/(5) *5=0*5` << the 5/5=1

`3n-57=0` << add 57 to both sides

`3n=57`

`(3n)/(3) = (57)/(3)` << divide 3 on both sides
57/3=19
OR
Pretend that n-19 = a

`(3a)/(5) =0`
Multiply 5 on both sides, so you get 3a=0. Then, you divide 3 on both sides.
a=0.
DO NOT FORGET, n-19 = a.
So, n-19=0.
Isolate n by adding 19 to both sides, and
n=19.