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PLEASE HELP THIS IS DUE TOMORROW

determine the quantity of work done when a crane lifts a 200-n block from 2 m above the ground to 6 m above the ground

User Cmo
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1 Answer

11 votes

Answer:

800 joules

Step-by-step explanation:

In physics, work is defined as

F = W x d (change)

Where is the word done, is the force that move the object and is the change of the position of the object.

In this case, we have

F = 200 N

d= 6m - 2m = 4m , remember that the difference refers to the actual subtraction between the final point and the initial point of the object.

Replacing these values, we have

W = 200 N x 4m

W = 800 joules

User Wholevinski
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