Question

suppose you reflect a triangle in quadrant 1 over the y-axis, then translate the image 2 units left and 3 units down. is there a single transformation that maps the preimage onto the image?Explain your reasoning.

Answer 1

no, because in order to get it where it is now, you reflected and translated it. those are two completely different transformations and the only way to get your image to where it is now is by utilizing both of those types of transformations simultaneously

Answer 2

No

Explanation:

You are aplying 3 different transformations to each point in the triangle. First you reflect it to the second cuadrant where the x values will be negative, then you translate it left which is moving 2 units to the left the x values and then you move it down which is smoving down 3 units to down the y value. For example:

If the vertices of the triangle ABC are:

`A(1,2)\\B(3,4)\\C(1.4)`

Then the vertices fo the final image are:

`A'(-3,-1)\\B'(-5,1)\\C'(-3,1)`