If y varies directly as the cube of x, what is the value of y in the ordered pairs (4, 16)(2, y)?

asked Jul 5, 2016 1.3k views

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$y=kx^3\\\\ 16=k\cdot4^3\\ 64k=16\\ k=(16)/(64)=(1)/(4)\\\\ y=(1)/(4)\cdot2^3\\ y=(1)/(4)\cdot8\\ \boxed{y=2}$

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