Answer:
Option B
Explanation:
Given that the 15 cards are numbered 1 to 15.
A card is picked at random. We have to find the probability that the card is odd or two
Let A - selected card is odd
B - selected card is 2
A and B are mutually exclusive
Hence P(AUB) = P(A)+P(B)
Since there are 1,3....15 i.e. 8 odd numbered cards
P(A) = 8/15
P(B) = 1/15 (since there is only one two)
Thus required prob = P(AUB) = 8/15+1/15
=9/15
=3/5
Hence option B