Question

The perimeter of a rectangle is 64 meters. If the length is 2 more

than twice the width, find the dimensions of the rectangle.

Answer 1

• 10 m and 22 m

Explanation:

Given rectangle with:

• P = 64 m
• l = 2w + 2

Find l and w

Solution

Perimeter formula:

• P = 2(l + w)

Substitute P and l and solve for w:

• 64 = 2(2w + 2 + w)
• 32 = 3w + 2
• 3w = 30
• w = 10 m

Find the value of l:

• l = 2(10) + 2 = 20 + 2 = 22 m

Dimensions are 10 m and 22 m