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How do you solve 4x+2y=10 x-y=13 using substitution

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\left \{ {{4x+2y=10} \atop {x-y=13}} \right.


x=13+y


4(13+y)+2y=10


52+4y+2y=10


6y=-42


y=-(42)/(6)=-7


y=-7


x=13-7=6


\left \{ {{x=6} \atop {y=-7}} \right.

User Akira Fukushima
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