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How many grams of sucrose, C12H22O11, are in a 94.2 mL sample of a 2.6 M sucrose solution?

User PKumar
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2 Answers

1 vote
Molar (M) means mol of solute in volume of solution (expressed by liters):


2.6(mol)/(L)\cdot 94.2\cdot 10^(-3)\ L = 0.245\ mol

The molecular weight of sucrose is: 12·12 + 22·1 + 11·16 = 342 g/mol.


0.245\ mol\ C_(12)H_(22)O_(11)\cdot (342\ g)/(1\ mol) = \bf 83.79\ g\ C_(12)H_(22)O_(11)
User Dave Rix
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1 vote
get the mass # of each element since its asking for grams
C- 12.011x12
H-1.008x22
O- 15.999x11
add all of those together to get the mass
put 2.6 moles on the top - so its the mass x 2.6 then divide by 94.2 Ml
User Capfan
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