Question

If a ball was thrown upward at 46.3 m/s how long would the ball stay in the air

Answer 1

`V = Vo + a.t`

The ball is against the vector of gravity. Then, the gravity will be negative.


`0 = 46,3 + (-9.8).t \\ t = (46.3)/(9.8) \\ t \approx 4.72`

The ball will stop in the air after approx. 4.72 seconds. And will take the same time to hit the ground.

It will stay approx. 9.44 seconds in the air.