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4 votes
If 0 < x < 1 , which of the following lists the numbers in increasing order ??

(a) √x , x , x²
(b) x² , x , √x
(c) x² , √x , x

2 Answers

6 votes
answer B


x = (1)/(4)

\sqrt{ (1)/(4) }= (1)/(2)

((1)/(4))^2 = (1)/(16)


(1)/(16)\ \textless \ (1)/(4)\ \textless \ (1)/(2)
User Sudmong
by
8.5k points
5 votes

Answer:

(b) x² , x , √x

Explanation:

Since, when x is a real number,

Such that 0 < x < 1

Then with increasing the exponent of x the value of x decreases,

That is, x with highest exponent is lowest,

Since,


2 > 1 > (1)/(2)

Thus, by the above statement,


x^2 < x < x^(1)/(2)

Hence, the numbers in increasing order is,

x² , x , √x

Where, 0 < x < 1

Option (b) is correct.

User Kirti Zare
by
8.3k points

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