Question

What is the fuction eqation for (0,-2)and (5,-1)

Answer 1

f(x) = 1/5 x - 2

-2 is your y intercept and using (y-y)/(x-x) you can get slope

(-1 - - 2)/ (5-0) = (-1+2) / (5) = 1/5

Answer 2

y = mx + b

m is the slope
b is the y-intercept

First find the slope


`slope = (y_2-y_1)/(x_2-x_1) = (-1+2)/(5-0)= (1)/(5)`

So far we have: y = 1/5x + b

Now we need to find b

y = 1/5x + b

Plug in (0,-2)

-2 = 1/5(0) + b

-2 = b

So the final equation is
`\boxed{y=(1)/(5)x-2}`