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Distance between (-1,2) (7,8)

2 Answers

2 votes

Answer: 10

Step-by-step explanation: In this problem, we're asked to find the distance between the points (-1,2) and (7,8) so we use the distance formula which states that the distance between two points is equal to


d =\sqrt{(x^(2) - x^(1))^(2) + (y^(2) - y^(1))^(2) }.

Our first point, (-1,2) represents (
^(x) 1,
^(y)1) and our second point,

(7,8) represents (
^(x)2,
^(y)2).

So, plugging the given information into the formula, we have
\sqrt{7 - (-1))^(2) + (8 - 2)^(2)}.

Next, we simplify inside the parentheses to get
\sqrt{(8)^(2) + (6)^(2)}.

Next, 8² is 64 and 6² is 36 so we have
√(64 + 36) or
√(100) which is 10.

So the distance between the points (-1,2) and (7,8) is 10.

User Bjorn Behrendt
by
8.4k points
3 votes

The distance between any two points is

square root of ( [difference in the 'y's]² + [difference in the 'x's]² )

Difference in the 'y's = 8 - 2 = 6
Difference in the 'x's = 7 - (-1) = 8

Distance between them =

square root of ( 6² + 8² ) =

square root of ( 36 + 64 ) =

square root of ( 100 ) = 10 .

User ZuzEL
by
8.2k points

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