Question

Need help with this equation! Can anybody lay out an answer please?

Use this equation; 4Fe + 3O2 -> 2Fe2O3.
If 96.0 grams of oxygen react, what mass of iron was oxidized?

A.) 32.0 g
B.) 96.0 g
C.) 167 g
D.) 223 g

Thanks!

Answer 1

As you can see in the reaction, for each
`3O_2` that reacts, two
`Fe_2O_3` are created.

There are
`(96.0)/(16)=6mol` of oxygens reacting, hence
`2*6/3=4` mols of iron will be oxidized, which represents
`24*55.8=\boxed{223g}`