Question

What is the diagonal of a rectangle with length 48 inches and width 40 inches?

Answer 1

i think its D=w2+l2=402+482≈ 62.482in

Answer 2

Use the Pythagorean Theorem:
`a^2 + b^2 = c^2`
You can do this because when you cut the rectangle in half with the diagonal, it forms a right triangle, making the diagonal the hypotenuse (c).


`40^2 + 48^2 = c^2`


`1600 + 2304 = c^2`


`3904 = c^2`


`√(3904) = √(c^2)`


`62.48 = c`

Diagonal: 62.48 inches