Question

Could you help me with math? 
2x^2 + 8x = 0
How to solve it?

Answer 1

`2x^2 + 8x = 0\\\\2x(x+4)=0\ \ \ \Leftrightarrow\ \ \ (2x=0\ /:2\ \ or\ \ \ x+4=0)\\\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=-4`

Answer 2

`2x^2 + 8x = 0\\ \\2x( x+4)=0 \\ \\2x=0 \ \ or \ \ x+4 = 0 \\ \\ x=0 \ \ or \ \ x = -4 \\ \\Answer : \ x=0 \ \ or \ \ x= -4`