Question

I need help with this math question:

Solve. Sin^2x-Sinx=0

I got 0,90,180,270 and 360 degrees. Anyone know if that's right

Answer 1

`\\ sin^2(x)-sin(x)=0 \\ sinx(sinx-1)=0 \\ \\ sinx=0 \\ x= \pi k~~k \in Z \\ x=0 \\ \\ sin(x)-1=0 \\ sin(x)=1 \\ x= ( \pi )/(2) +2 \pi k~~k \in Z`